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Waves — Medium JEE physics MCQ

**[JEE Mains 2026]** In an open organ pipe, the 3rd and 6th harmonic frequencies differ by 3200 Hz. If the speed of sound is 320 m/s, find the length of the organ pipe.
  1. A. 10 cm
  2. B. 15 cm
  3. C. 20 cm
  4. D. 25 cm

Solution

For an open pipe, fₙ = nv/(2L). f₆ - f₃ = 6v/(2L) - 3v/(2L) = 3v/(2L) = 3200 Hz. L = 3 × 320 / (2 × 3200) = 960/6400 = 0.15 m = 15 cm.

PHYSICS

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[JEE Mains 2026] In an open organ pipe, the 3rd and 6th harmonic frequencies differ by 3200 Hz. If the speed of sound is 320 m/s, find the length of the organ pipe.
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Waves — Medium JEE Physics MCQ | MyGoalPrep