Wave Optics — Easy JEE physics MCQ
In a Young's double slit experiment, the slit separation is 0.1 mm and the screen is placed 1 m from the slits. If light of wavelength 600 nm is used, the fringe width is:
- A. 3 mm
- B. 6 mm
- C. 0.6 mm
- D. 0.3 mm
Solution
Fringe width β = λD/d = (600 × 10⁻⁹ × 1)/(0.1 × 10⁻³) = 6 × 10⁻³ m = 6 mm.