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Units And Dimensions — Easy JEE physics MCQ

The dimensional formula of Planck's constant is:
  1. A. $[ML^2T^{-1}]$
  2. B. $[ML^2T^{-2}]$
  3. C. $[MLT^{-1}]$
  4. D. $[ML^2T^{-3}]$

Solution

$E = h\nu \Rightarrow h = E/\nu$ $[h] = \frac{[ML^2T^{-2}]}{[T^{-1}]} = [ML^2T^{-1}]$

PHYSICS

easy • PYQ Reworded
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The dimensional formula of Planck's constant is:
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Units And Dimensions — Easy JEE Physics MCQ | MyGoalPrep