Units And Dimensions — Easy JEE physics MCQ
**[JEE Mains 2026]** Find the dimensions of the expression ε₀E²t, where ε₀ is permittivity, E is electric field, and t is time.
- A. [ML²T⁻³]
- B. [ML⁻¹T⁻¹]
- C. [MT⁻²]
- D. [ML⁻¹T⁻²]
Solution
[ε₀] = [M⁻¹L⁻³T⁴A²], [E] = [MLT⁻³A⁻¹], [t] = [T].
[ε₀E²t] = [M⁻¹L⁻³T⁴A²][M²L²T⁻⁶A⁻²][T] = [ML⁻¹T⁻¹].