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ThermodynamicsHard JEE physics MCQ

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure $P_{i}=10^{5} \mathrm{~Pa}$ and volume $V_{i}=10^{-3} \mathrm{~m}^{3}$ changes to a final state at $P_{f}=(1 / 32) \times 10^{5} \mathrm{~Pa}$ and $V_{f}=8 \times 10^{-3} \mathrm{~m}^{3}$ in an adiabatic quasi-static process, such that $P^{3} V^{5}=$ constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at $P_{i}$ followed by an isochoric (isovolumetric) process at volume $V_{f}$. The amount of heat supplied to the system in the two-step process is approximately
  1. A. $112 \mathrm{~J}$
  2. B. $294 \mathrm{~J}$
  3. C. $588 \mathrm{~J}$
  4. D. $813 \mathrm{~J}$

Solution

The correct option is **C**.

PHYSICS

hardPYQ Reworded
Question
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A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi=105 PaP_{i}=10^{5} \mathrm{~Pa} and volume Vi=103 m3V_{i}=10^{-3} \mathrm{~m}^{3} changes to a final state at Pf=(1/32)×105 PaP_{f}=(1 / 32) \times 10^{5} \mathrm{~Pa} and Vf=8×103 m3V_{f}=8 \times 10^{-3} \mathrm{~m}^{3} in an adiabatic quasi-static process, such that P3V5=P^{3} V^{5}= constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at PiP_{i} followed by an isochoric (isovolumetric) process at volume VfV_{f}. The amount of heat supplied to the system in the two-step process is approximately
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Thermodynamics — Hard JEE Physics MCQ | MyGoalPrep