MyGoalPrep LogoMyGoalPrep.com

Thermal Properties — Medium JEE physics MCQ

**[JEE Mains 2026]** Two rods of equal length 60 cm each are joined together end to end. The coefficients of linear expansion of the rods are 2 × 10⁻⁵ /°C and 3 × 10⁻⁵ /°C. If the temperature is increased from 20°C to 120°C, find the final length of the combination (in cm).
  1. A. 120.15
  2. B. 120.30
  3. C. 120.45
  4. D. 120.60

Solution

ΔL₁ = L₁α₁ΔT = 60 × 2×10⁻⁵ × 100 = 0.12 cm. ΔL₂ = L₂α₂ΔT = 60 × 3×10⁻⁵ × 100 = 0.18 cm. Final length = 120 + 0.12 + 0.18 = 120.30 cm.

PHYSICS

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
[JEE Mains 2026] Two rods of equal length 60 cm each are joined together end to end. The coefficients of linear expansion of the rods are 2 × 10⁻⁵ /°C and 3 × 10⁻⁵ /°C. If the temperature is increased from 20°C to 120°C, find the final length of the combination (in cm).
AI hints
Ask for a nudge. Keep it specific.
Thermal Properties — Medium JEE Physics MCQ | MyGoalPrep