Kinematics — Medium JEE physics MCQ
**[JEE Mains 2026]** A particle is projected at an angle of 60° with the ground. When the projectile makes an angle of 30° with the horizontal, its speed is 20 m/s. What is the initial velocity of the projectile?
- A. 10 m/s
- B. 20√3 m/s
- C. 40 m/s
- D. 40/√3 m/s
Solution
The horizontal component of velocity remains constant: v cos30° = u cos60°.
So, 20 × (√3/2) = u × (1/2), giving u = 20√3 m/s × 2/√3 = 40/√3 m/s.
