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KinematicsMedium JEE physics MCQ

**[JEE Mains 2026]** A particle is projected at an angle of 60° with the ground. When the projectile makes an angle of 30° with the horizontal, its speed is 20 m/s. What is the initial velocity of the projectile?
  1. A. 10 m/s
  2. B. 20√3 m/s
  3. C. 40 m/s
  4. D. 40/√3 m/s

Solution

The horizontal component of velocity remains constant: v cos30° = u cos60°. So, 20 × (√3/2) = u × (1/2), giving u = 20√3 m/s × 2/√3 = 40/√3 m/s.

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[JEE Mains 2026] A particle is projected at an angle of 60° with the ground. When the projectile makes an angle of 30° with the horizontal, its speed is 20 m/s. What is the initial velocity of the projectile?
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