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Photoelectric Effect — Medium JEE physics MCQ

The work function of a metal is 2 eV. Light of wavelength 400 nm is incident on it. The maximum kinetic energy of the emitted photoelectrons is: (h = 6.6 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, 1 eV = 1.6 × 10⁻¹⁹ J)
  1. A. 0.5 eV
  2. B. 1.1 eV
  3. C. 2.0 eV
  4. D. 3.1 eV

Solution

Energy of photon E = hc/λ = (6.6 × 10⁻³⁴ × 3 × 10⁸)/(400 × 10⁻⁹) = 4.95 × 10⁻¹⁹ J ≈ 3.1 eV. Maximum KE = E - φ = 3.1 - 2 = 1.1 eV.

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The work function of a metal is 2 eV. Light of wavelength 400 nm is incident on it. The maximum kinetic energy of the emitted photoelectrons is: (h = 6.6 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, 1 eV = 1.6 × 10⁻¹⁹ J)
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Photoelectric Effect — Medium JEE Physics MCQ | MyGoalPrep