Oscillations — Easy JEE physics MCQ
If the length of a simple pendulum is increased by $44\%$, the percentage change in time period is:
- A. $20\%$
- B. $22\%$
- C. $44\%$
- D. $10\%$
Solution
$T \propto \sqrt{L}$
$\frac{T'}{T} = \sqrt{\frac{1.44L}{L}} = 1.2$
% change $= 20\%$
