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Laws Of Motion — Medium JEE physics MCQ

**[JEE Mains 2026]** Two masses M and 4M are placed at a distance d apart. A third mass m is placed between them. If the net gravitational force on mass m due to M and 4M is F when m is at distance d/3 from M, what is F in terms of GmM/d²?
  1. A. 9GmM/d²
  2. B. 0
  3. C. 3GmM/d²
  4. D. 6GmM/d²

Solution

Force due to M on m: F₁ = GmM/(d/3)² = 9GmM/d² (towards M). Force due to 4M on m: F₂ = Gm(4M)/(2d/3)² = 9GmM/d² (towards 4M). Since forces are equal and opposite, net force F = 0.

PHYSICS

medium • PYQ Reworded
Question
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[JEE Mains 2026] Two masses M and 4M are placed at a distance d apart. A third mass m is placed between them. If the net gravitational force on mass m due to M and 4M is F when m is at distance d/3 from M, what is F in terms of GmM/d²?
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Laws Of Motion — Medium JEE Physics MCQ | MyGoalPrep