Mechanical Properties — Easy JEE physics MCQ
A wire of length $2$ m and cross-sectional area $10^{-6}$ m² stretches by $0.1$ mm under a load of $1$ kg. The Young's modulus is (g = $10$ m/s²):
- A. $2 \times 10^{11}$ Pa
- B. $1 \times 10^{11}$ Pa
- C. $2 \times 10^{10}$ Pa
- D. $1 \times 10^{10}$ Pa
Solution
$Y = \frac{FL}{A\Delta L} = \frac{10 \times 2}{10^{-6} \times 0.1 \times 10^{-3}} = \frac{20}{10^{-10}} = 2 \times 10^{11}$ Pa
