Magnetic Effects — Easy JEE physics MCQ
A wire of length $0.5$ m carrying current $2$ A is placed perpendicular to a magnetic field of $0.4$ T. The force on the wire is:
- A. $0.4$ N
- B. $0.8$ N
- C. $0.2$ N
- D. $1.6$ N
Solution
$F = BIL = 0.4 \times 2 \times 0.5 = 0.4$ N
