MyGoalPrep LogoMyGoalPrep.com

Laws Of Motion — Easy JEE physics MCQ

A force acts on a body of mass $5$ kg for $2$ s. If the velocity changes from $3$ m/s to $7$ m/s, the force applied is:
  1. A. $10$ N
  2. B. $15$ N
  3. C. $20$ N
  4. D. $8$ N

Solution

$F = ma = m\frac{\Delta v}{\Delta t} = 5 \times \frac{7-3}{2} = 5 \times 2 = 10$ N

PHYSICS

easy • PYQ Reworded
Question
Read carefully, then pick the best option.
A force acts on a body of mass 55 kg for 22 s. If the velocity changes from 33 m/s to 77 m/s, the force applied is:
AI hints
Ask for a nudge. Keep it specific.
Laws Of Motion — Easy JEE Physics MCQ | MyGoalPrep