Kinematics — Easy JEE physics MCQ
A body starting from rest accelerates uniformly at $2$ m/s². The distance covered in the 5th second is:
- A. $9$ m
- B. $10$ m
- C. $11$ m
- D. $8$ m
Solution
Distance in nth second: $s_n = u + a(n - \frac{1}{2})$
$s_5 = 0 + 2(5 - 0.5) = 2 \times 4.5 = 9$ m
