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Fluid Mechanics — Easy JEE physics MCQ

The pressure at the bottom of a tank of water of depth $10$ m is (g = $10$ m/s², atmospheric pressure = $10^5$ Pa):
  1. A. $2 \times 10^5$ Pa
  2. B. $1.5 \times 10^5$ Pa
  3. C. $10^5$ Pa
  4. D. $10^4$ Pa

Solution

$P = P_0 + \rho gh = 10^5 + 1000 \times 10 \times 10 = 10^5 + 10^5 = 2 \times 10^5$ Pa

PHYSICS

easy • PYQ Reworded
Question
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The pressure at the bottom of a tank of water of depth 1010 m is (g = 1010 m/s², atmospheric pressure = 10510^5 Pa):
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Fluid Mechanics — Easy JEE Physics MCQ | MyGoalPrep