Electromagnetism — Hard JEE physics MCQ
A series LCR circuit is connected to a $45 \sin (\omega t)$ Volt source. The resonant angular frequency of the circuit is $10^{5} \mathrm{rad} \mathrm{s}^{-1}$ and current amplitude at resonance is $I_{0}$. When the angular frequency of the source is $\omega=8 \times 10^{4} \mathrm{rad} \mathrm{s}^{-1}$, the current amplitude in the circuit is $0.05 I_{0}$. If $L=50 \mathrm{mH}$, match each entry in List-I with an appropriate value from List-II and choose the correct option.
\textbf{List-I}
(P) $I_{0}$ in $\mathrm{mA}$
(Q) The quality factor of the circuit
(R) The bandwidth of the circuit in $\mathrm{rad} \mathrm{s}^{-1}$
(S) The peak power dissipated at resonance in Watt
\textbf{List-II}
(1) 44.4
(2) 18
(3) 400
(4) 2250
(5) 500
- A. $P \rightarrow 2, Q \rightarrow 3, R \rightarrow 5, S \rightarrow 1$
- B. $P \rightarrow 3, Q \rightarrow 1, R \rightarrow 4, S \rightarrow 2$
- C. $P \rightarrow 4, Q \rightarrow 5, R \rightarrow 3, S \rightarrow 1$
- D. $P \rightarrow 4, Q \rightarrow 2, R \rightarrow 1, S \rightarrow 5$
Solution
The correct option is **B**.