Electromagnetism — Easy JEE physics MCQ
A circular loop of radius $7$ cm carries a current of $2$ A. Its magnetic moment is:
- A. $3.08 \times 10^{-2}$ A·m²
- B. $0.88$ A·m²
- C. $0.44$ A·m²
- D. $6.16 \times 10^{-2}$ A·m²
Solution
$M = IA = I\pi r^2 = 2 \times \pi \times (0.07)^2 = 2 \times 3.14 \times 0.0049 \approx 3.08 \times 10^{-2}$ A·m²
