Circular Motion — Easy JEE physics MCQA particle moves in a circle of radius $2$ m with constant speed $4$ m/s. Its centripetal acceleration is:A. $8$ m/s²B. $2$ m/s²C. $16$ m/s²D. $4$ m/s²Solution$a_c = \frac{v^2}{r} = \frac{16}{2} = 8$ m/s²