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Alternating Current — Easy JEE physics MCQ

In a series LCR circuit, $L = 0.1$ H and $C = 10$ μF. The resonant frequency is:
  1. A. $159$ Hz
  2. B. $500$ Hz
  3. C. $100$ Hz
  4. D. $1000$ Hz

Solution

$f_0 = \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\pi\sqrt{0.1 \times 10^{-5}}} = \frac{1}{2\pi \times 10^{-3}} \approx 159$ Hz

PHYSICS

easy • PYQ Reworded
Question
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In a series LCR circuit, L=0.1L = 0.1 H and C=10C = 10 μF. The resonant frequency is:
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Alternating Current — Easy JEE Physics MCQ | MyGoalPrep