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TrigonometryMedium JEE math MCQ

Let $-\frac{\pi}{6}<\theta<-\frac{\pi}{12}$. Suppose $\alpha_{1}$ and $\beta_{1}$ are the roots of the equation $x^{2}-2 x \sec \theta+1=0$ and $\alpha_{2}$ and $\beta_{2}$ are the roots of the equation $x^{2}+2 x \tan \theta-1=0$. If $\alpha_{1}>\beta_{1}$ and $\alpha_{2}>\beta_{2}$, then $\alpha_{1}+\beta_{2}$ equals
  1. A. $2(\sec \theta-\tan \theta)$
  2. B. $2 \sec \theta$
  3. C. $-2 \tan \theta$
  4. D. 0

Solution

The correct option is **C**.

MATH

mediumPYQ Reworded
Question
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Let π6<θ<π12-\frac{\pi}{6}<\theta<-\frac{\pi}{12}. Suppose α1\alpha_{1} and β1\beta_{1} are the roots of the equation x22xsecθ+1=0x^{2}-2 x \sec \theta+1=0 and α2\alpha_{2} and β2\beta_{2} are the roots of the equation x2+2xtanθ1=0x^{2}+2 x \tan \theta-1=0. If α1>β1\alpha_{1}>\beta_{1} and α2>β2\alpha_{2}>\beta_{2}, then α1+β2\alpha_{1}+\beta_{2} equals
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Trigonometry — Medium JEE Mathematics MCQ | MyGoalPrep