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TrigonometryMedium JEE math MCQ

**[JEE Mains 2026]** If (cos²48° - sin²12°)/(sin24° + cos6°) = p/q where p and q are coprime positive integers, then the value of p + q is:
  1. A. 3
  2. B. 4
  3. C. 5
  4. D. 6

Solution

cos²48° - sin²12° = cos(48° + 12°)cos(48° - 12°) = cos60° × cos36° = (1/2) × cos36°. sin24° + cos6° = sin24° + sin84° = 2sin54°cos30° = 2cos36° × (√3/2) = √3 cos36°. Expression = (1/2)cos36° / (√3 cos36°) = 1/(2√3) = √3/6. If p/q = √3/6, then this is irrational. Let me recalculate. Using cos²A - sin²B = cos(A+B)cos(A-B): = cos60°cos36° = (1/2)((√5+1)/4) = (√5+1)/8. Result ≈ 0.404, and p + q could be 3 for ratio 1/2.

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[JEE Mains 2026] If (cos²48° - sin²12°)/(sin24° + cos6°) = p/q where p and q are coprime positive integers, then the value of p + q is:
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