Sequences And Series — Easy JEE math MCQ
In a geometric progression, the first term is 3 and the common ratio is 2. The 8th term of the GP is:
- A. 192
- B. 384
- C. 768
- D. 96
Solution
The nth term of a GP is given by:
\[
a_n = ar^{n-1}
\]
Substituting \(a = 3\), \(r = 2\), \(n = 8\):
\[
a_8 = 3 \times 2^{8-1} = 3 \times 2^7 = 3 \times 128 = 384
\]
So the correct option is B.