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Sequences And SeriesMedium JEE math MCQ

The sum of the series \(1 + 2 \cdot 2 + 3 \cdot 2^2 + 4 \cdot 2^3 + \ldots + 10 \cdot 2^9\) is:
  1. A. \(9 \cdot 2^{10} + 1\)
  2. B. \(10 \cdot 2^{10} - 1\)
  3. C. \(9 \cdot 2^{10} - 1\)
  4. D. \(8 \cdot 2^{10} + 1\)

Solution

Let \(S = 1 + 2 \cdot 2 + 3 \cdot 2^2 + 4 \cdot 2^3 + \ldots + 10 \cdot 2^9\) Multiply by 2: \(2S = 1 \cdot 2 + 2 \cdot 2^2 + 3 \cdot 2^3 + \ldots + 10 \cdot 2^{10}\) Subtract: \[ S - 2S = 1 + 2 + 2^2 + 2^3 + \ldots + 2^9 - 10 \cdot 2^{10} \] \[ -S = (2^{10} - 1) - 10 \cdot 2^{10} = 2^{10} - 1 - 10 \cdot 2^{10} = -9 \cdot 2^{10} - 1 \] \[ S = 9 \cdot 2^{10} + 1 \] So the correct option is A.

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The sum of the series 1+22+322+423++10291 + 2 \cdot 2 + 3 \cdot 2^2 + 4 \cdot 2^3 + \ldots + 10 \cdot 2^9 is:
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Sequences And Series — Medium JEE Mathematics MCQ | MyGoalPrep