Probability — Medium JEE math MCQ
Three randomly chosen nonnegative integers $x, y$ and $z$ are found to satisfy the equation $x+y+z=10$. Then the probability that $z$ is even, is
- A. $\frac{36}{55}$
- B. $\frac{6}{11}$
- C. $\frac{1}{2}$
- D. $\frac{5}{11}$
Solution
The correct option is **B**.