Straight Lines — Easy JEE math MCQThe slope of the line $3x + 4y - 7 = 0$ is:A. $-\frac{3}{4}$B. $\frac{3}{4}$C. $\frac{4}{3}$D. $-\frac{4}{3}$Solution$4y = -3x + 7 \Rightarrow y = -\frac{3}{4}x + \frac{7}{4}$ Slope $= -\frac{3}{4}$