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Linear Programming — Easy JEE math MCQ

The corner points of a feasible region are $(0, 0)$, $(4, 0)$, $(2, 3)$, $(0, 4)$. The maximum value of $Z = 3x + 2y$ is:
  1. A. $12$
  2. B. $8$
  3. C. $13$
  4. D. $10$

Solution

At $(0, 0)$: $Z = 0$ At $(4, 0)$: $Z = 12$ At $(2, 3)$: $Z = 6 + 6 = 12$ At $(0, 4)$: $Z = 8$ Maximum $Z = 12$

MATH

easy • PYQ Reworded
Question
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The corner points of a feasible region are (0,0)(0, 0), (4,0)(4, 0), (2,3)(2, 3), (0,4)(0, 4). The maximum value of Z=3x+2yZ = 3x + 2y is:
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