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Inverse Trigonometry — Easy JEE math MCQ

The principal value of $\sin^{-1}\left(\frac{1}{2}\right)$ is:
  1. A. $\frac{\pi}{6}$
  2. B. $\frac{\pi}{3}$
  3. C. $\frac{5\pi}{6}$
  4. D. $-\frac{\pi}{6}$

Solution

$\sin^{-1}\left(\frac{1}{2}\right) = \frac{\pi}{6}$ (principal value lies in $[-\frac{\pi}{2}, \frac{\pi}{2}]$)

MATH

easy • PYQ Reworded
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The principal value of sin⁡−1(12)\sin^{-1}\left(\frac{1}{2}\right) is:
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Inverse Trigonometry — Easy JEE Mathematics MCQ | MyGoalPrep