Height And Distance — Easy JEE math MCQ
The angle of elevation of the top of a tower from a point $50$ m away from its base is $60°$. The height of the tower is:
- A. $50\sqrt{3}$ m
- B. $\frac{50}{\sqrt{3}}$ m
- C. $50$ m
- D. $100$ m
Solution
$\tan 60° = \frac{h}{50}$
$\sqrt{3} = \frac{h}{50}$
$h = 50\sqrt{3}$ m
