General — Medium JEE math MCQThe least value of $\alpha \in \mathbb{R}$ for which $4 \alpha x^{2}+\frac{1}{x} \geq 1$, for all $x>0$, isA. $\frac{1}{64}$B. $\frac{1}{32}$C. $\frac{1}{27}$D. $\frac{1}{25}$SolutionThe correct option is **C**.