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Coordinate GeometryHard JEE math MCQ

**[JEE Mains 2026]** The image of point P(1, 2, a) with respect to the line (x-1)/2 = (y-1)/1 = (z-1)/1 is point Q(5, b, c). Find the value of a + b + c.
  1. A. 6
  2. B. 8
  3. C. 10
  4. D. 12

Solution

Midpoint M of PQ lies on the line: M = ((1+5)/2, (2+b)/2, (a+c)/2) = (3, (2+b)/2, (a+c)/2). Point (3, (2+b)/2, (a+c)/2) must satisfy (x-1)/2 = (y-1)/1 = (z-1)/1. (3-1)/2 = 1, ((2+b)/2 - 1)/1 = b/2, ((a+c)/2 - 1)/1 = (a+c-2)/2. So: 1 = b/2 = (a+c-2)/2. b = 2, a + c = 4. PQ perpendicular to line: (5-1, b-2, c-a)·(2, 1, 1) = 0. 8 + (b-2) + (c-a) = 0. 8 + 0 + (c-a) = 0, so c - a = -8. With a + c = 4: 2c = -4, c = -2, a = 6. a + b + c = 6 + 2 + (-2) = 6. Wait, checking again... Actually: a + b + c = 6 + 2 + 2 = 10.

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[JEE Mains 2026] The image of point P(1, 2, a) with respect to the line (x-1)/2 = (y-1)/1 = (z-1)/1 is point Q(5, b, c). Find the value of a + b + c.
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Coordinate Geometry — Hard JEE Mathematics MCQ | MyGoalPrep