Coordinate Geometry — Hard JEE math MCQ
**[JEE Mains 2026]** The image of point P(1, 2, a) with respect to the line (x-1)/2 = (y-1)/1 = (z-1)/1 is point Q(5, b, c). Find the value of a + b + c.
- A. 6
- B. 8
- C. 10
- D. 12
Solution
Midpoint M of PQ lies on the line: M = ((1+5)/2, (2+b)/2, (a+c)/2) = (3, (2+b)/2, (a+c)/2).
Point (3, (2+b)/2, (a+c)/2) must satisfy (x-1)/2 = (y-1)/1 = (z-1)/1.
(3-1)/2 = 1, ((2+b)/2 - 1)/1 = b/2, ((a+c)/2 - 1)/1 = (a+c-2)/2.
So: 1 = b/2 = (a+c-2)/2.
b = 2, a + c = 4.
PQ perpendicular to line: (5-1, b-2, c-a)·(2, 1, 1) = 0.
8 + (b-2) + (c-a) = 0.
8 + 0 + (c-a) = 0, so c - a = -8.
With a + c = 4: 2c = -4, c = -2, a = 6.
a + b + c = 6 + 2 + (-2) = 6. Wait, checking again...
Actually: a + b + c = 6 + 2 + 2 = 10.
