Coordinate Geometry — Easy JEE math MCQ
The distance between the parallel lines 3x + 4y - 5 = 0 and 3x + 4y + 10 = 0 is:
- A. 1
- B. 3
- C. 5
- D. 15
Solution
Distance = |c₁ - c₂| / √(a² + b²) = |-5 - 10| / √(9 + 16) = 15/5 = 3.
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The distance between the parallel lines 3x + 4y - 5 = 0 and 3x + 4y + 10 = 0 is:
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