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Coordinate Geometry — Easy JEE math MCQ

A line $y=m x+1$ intersects the circle $(x-3)^{2}+(y+2)^{2}=25$ at the points $P$ and $Q$. If the midpoint of the line segment $P Q$ has $x$-coordinate $-\frac{3}{5}$, then which one of the following options is correct?
  1. A. $-3 \leq m<-1$
  2. B. $2 \leq m<4$
  3. C. $4 \leq m<6$
  4. D. $6 \leq m<8$

Solution

The correct option is **B**.

MATH

easy • PYQ Reworded
Question
Read carefully, then pick the best option.
A line y=mx+1y=m x+1 intersects the circle (x−3)2+(y+2)2=25(x-3)^{2}+(y+2)^{2}=25 at the points PP and QQ. If the midpoint of the line segment PQP Q has xx-coordinate −35-\frac{3}{5}, then which one of the following options is correct?
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Coordinate Geometry — Easy JEE Mathematics MCQ | MyGoalPrep