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Continuity — Medium JEE math MCQ

The function $f(x) = \frac{x^2 - 4}{x - 2}$ is discontinuous at:
  1. A. $x = 2$
  2. B. $x = -2$
  3. C. $x = 0$
  4. D. $x = 4$

Solution

$f(x) = \frac{(x-2)(x+2)}{x-2}$ is undefined at $x = 2$ (division by zero), hence discontinuous at $x = 2$.

MATH

medium • PYQ Reworded
Question
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The function f(x)=x2−4x−2f(x) = \frac{x^2 - 4}{x - 2} is discontinuous at:
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Continuity — Medium JEE Mathematics MCQ | MyGoalPrep