Binomial Theorem — Medium JEE math MCQThe coefficient of $x^3$ in the expansion of $(1+x)^{10}$ is:A. $120$B. $45$C. $210$D. $252$SolutionCoefficient of $x^3$ = $^{10}C_3 = \frac{10!}{3!7!} = \frac{10 \times 9 \times 8}{6} = 120$