Area Under Curves — Easy JEE math MCQ
The area bounded by $y = x^2$, $x$-axis, $x = 0$ and $x = 2$ is:
- A. $\frac{8}{3}$ sq units
- B. $4$ sq units
- C. $\frac{4}{3}$ sq units
- D. $2$ sq units
Solution
Area $= \int_0^2 x^2 dx = \left[\frac{x^3}{3}\right]_0^2 = \frac{8}{3}$
