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3d Geometry — Easy JEE math MCQ

The distance between points $(1, 2, 3)$ and $(4, 6, 3)$ is:
  1. A. $5$
  2. B. $\sqrt{26}$
  3. C. $6$
  4. D. $\sqrt{34}$

Solution

$d = \sqrt{(4-1)^2 + (6-2)^2 + (3-3)^2} = \sqrt{9 + 16 + 0} = \sqrt{25} = 5$

MATH

easy • PYQ Reworded
Question
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The distance between points (1,2,3)(1, 2, 3) and (4,6,3)(4, 6, 3) is:
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3d Geometry — Easy JEE Mathematics MCQ | MyGoalPrep