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Jee Main 2025Medium JEE math MCQ

Let the function \( f(x) = (x^2 + 1) \left|x^2 - ax + 2 \right| + \cos |x| \) be not differentiable at the two points \( x = \alpha = 2 \) and \( x = \beta \). Then the distance of the point \((\alpha, \beta)\) from the line \(12x + 5y + 10 = 0\) is equal to
  1. A. 5
  2. B. 4
  3. C. 3
  4. D. 2

Solution

The correct option is **C**. (C. 3)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
Let the function f(x)=(x2+1)x2ax+2+cosx f(x) = (x^2 + 1) \left|x^2 - ax + 2 \right| + \cos |x| be not differentiable at the two points x=α=2 x = \alpha = 2 and x=β x = \beta . Then the distance of the point (α,β)(\alpha, \beta) from the line 12x+5y+10=012x + 5y + 10 = 0 is equal to
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep