Jee Main 2025 — Medium JEE math MCQ
Let the line \( x + y = 1 \) meet the axes of \( x \) and \( y \) at \( A \) and \( B \), respectively. A right angled triangle \( AMN \) is inscribed in the triangle \( OAB \), where \( O \) is the origin and the points \( M \) and \( N \) lie on the lines \( OB \) and \( AB \), respectively. If the area of the triangle \( AMN \) is \( \frac{4}{5} \) of the area of the triangle \( OAB \) and \( AN : NB = \lambda : 1 \), then the sum of all possible value(s) of \( \lambda \) is
- A. 2
- B. \( \frac{5}{2} \)
- C. \( \frac{1}{2} \)
- D. \( \frac{13}{6} \)
Solution
The correct option is **A**. (A. 2)
