Jee Main 2025 — Hard JEE math MCQ
If for the solution curve \( y = f(x) \) of the differential equation \( \frac{dy}{dx} + (\tan x)y = \frac{2 + \sec x}{(1 + 2\sec x)^2} \), \( x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \), then \( f\left(\frac{\pi}{4}\right) \) is equal to
- A. \( \frac{\sqrt{3} - 1}{10(4+\sqrt{3})} \)
- B. \( \frac{\sqrt{3} - 1}{2\sqrt{3} - 2} \)
- C. \( \frac{\sqrt{3} - 1}{10(4+\sqrt{3})} \)
- D. \( \frac{5 - \sqrt{3}}{14} \)
Solution
The correct option is **D**. (D. \( \frac{5 - \sqrt{3}}{14} \))
