Jee Main 2025 — Medium JEE math MCQ
Let \( ABC \) be a triangle formed by the lines \( 7x - 6y + 3 = 0, x + 2y - 31 = 0 \) and \( 9x - 2y - 19 = 0 \). Let the point \((h, k)\) be the image of the centroid of \( \Delta ABC \) in the line \( 3x + 6y - 53 = 0 \). Then \( h^2 + k^2 + hk \) is equal to:
- A. \quad 47 \\
- B. \quad 36 \\
- C. \quad 47 \\
- D. \quad 40 \\
Solution
The correct option is **B**. (B. \quad 36 \\)
