Jee Main 2025 — Medium JEE math MCQ
Let \(\{a_n\}\) be a sequence such that \(a_0 = 0, a_1 = \frac{1}{2}\) and \(2a_{n+2} = 5a_{n+1} - 3a_n, n = 0, 1, 2, 3, \ldots\). Then \(\sum_{k=1}^{100} a_k\) is equal to
- A. \( 3a_{99} - 100 \)
- B. \( 3a_{100} + 100 \)
- C. \( 3a_{99} + 100 \)
- D. \( 3a_{100} - 100 \)
Solution
The correct option is **B**. (B. \( 3a_{100} + 100 \))
