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Jee Main 2025Medium JEE math MCQ

Let \( f : \mathbb{R} \to \mathbb{R} \) be a function defined by \( f(x) = (2 + 3a)x^2 + \left( \frac{2a+7}{2} \right)x + b, a \neq 1. \) If \( f(x + y) = f(x) + f(y) + 1 - \frac{1}{2}xy \), then the value of \( 28 \sum_{i=1}^{5} |f(i)| \) is
  1. A. 545
  2. B. 715
  3. C. 735
  4. D. 675

Solution

The correct option is **D**. (D. 675)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
Let f:RR f : \mathbb{R} \to \mathbb{R} be a function defined by f(x)=(2+3a)x2+(2a+72)x+b,a1. f(x) = (2 + 3a)x^2 + \left( \frac{2a+7}{2} \right)x + b, a \neq 1. If f(x+y)=f(x)+f(y)+112xy f(x + y) = f(x) + f(y) + 1 - \frac{1}{2}xy , then the value of 28i=15f(i) 28 \sum_{i=1}^{5} |f(i)| is
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep