Jee Main 2025 — Medium JEE math MCQ
Let \(S_n = \frac{1}{2} + \frac{1}{9} + \frac{1}{12} + \frac{1}{21} + \ldots \) upto \(n\) terms. If the sum of the first six terms of an A.P. with first term \(-p\) and common difference \(p\) is \(\sqrt{2025} S_{2025}\), then the absolute difference between 20th and 15th terms of the A.P. is
- A. 20
- B. 90
- C. 45
- D. 25
Solution
The correct option is **D**. (D. 25)
