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Jee Main 2025 — Medium JEE math MCQ

Let the shortest distance from \((a, 0), a > 0\) to the parabola \(y^2 = 4x\) be 4. Then the equation of the circle passing through the point \((a, 0)\) and the focus of the parabola, and having its centre on the axis of the parabola is
  1. A. \(x^2 + y^2 - 10x + 9 = 0\)
  2. B. \(x^2 + y^2 - 6x + 5 = 0\)
  3. C. \(x^2 + y^2 - 4x + 3 = 0\)
  4. D. \(x^2 + y^2 - 8x + 7 = 0\)

Solution

The correct option is **B**. (B. \(x^2 + y^2 - 6x + 5 = 0\))

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
Let the shortest distance from (a,0),a>0(a, 0), a > 0 to the parabola y2=4xy^2 = 4x be 4. Then the equation of the circle passing through the point (a,0)(a, 0) and the focus of the parabola, and having its centre on the axis of the parabola is
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep