Jee Main 2025 — Hard JEE math MCQ
Let \( A = [a_{ij}] \) be a \( 3 \times 3 \) matrix such that \[ A \begin{bmatrix} 0 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix}, A \begin{bmatrix} 1 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} \text{ and } A \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} = \begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} \], then \( a_{23} \) equals
- A. -1
- B. 2
- C. 1
- D. 0
Solution
The correct option is **A**. (A. -1)
