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Jee Main 2025Medium JEE math MCQ

The length of the chord of the ellipse \( \frac{x^2}{4} + \frac{y^2}{3} = 1 \), whose mid-point is \((1, \frac{1}{2})\), is
  1. A. \( \frac{5}{3} \sqrt{15} \)
  2. B. \( \frac{1}{3} \sqrt{15} \)
  3. C. \( \frac{2}{3} \sqrt{15} \)
  4. D. \( \sqrt{15} \)

Solution

The correct option is **C**. (C. \( \frac{2}{3} \sqrt{15} \))

MATH

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Question
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The length of the chord of the ellipse x24+y23=1 \frac{x^2}{4} + \frac{y^2}{3} = 1 , whose mid-point is (1,12)(1, \frac{1}{2}), is
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep