Jee Main 2025 — Medium JEE math MCQ
The length of the chord of the ellipse \( \frac{x^2}{4} + \frac{y^2}{3} = 1 \), whose mid-point is \((1, \frac{1}{2})\), is
- A. \( \frac{5}{3} \sqrt{15} \)
- B. \( \frac{1}{3} \sqrt{15} \)
- C. \( \frac{2}{3} \sqrt{15} \)
- D. \( \sqrt{15} \)
Solution
The correct option is **C**. (C. \( \frac{2}{3} \sqrt{15} \))
