Jee Main 2025 — Medium JEE math MCQ
Let the curve \( z(1 + i) + \bar{z}(1 - i) = 4 \), \( z \in \mathbb{C} \), divide the region \( |z - 3| \leq 1 \) into two parts of areas \( \alpha \) and \( \beta \). Then \( |\alpha - \beta| \) equals
- A. \( 1 + \frac{\pi}{2} \)
- B. \( 1 + \frac{\pi}{3} \)
- C. \( 1 + \frac{\pi}{6} \)
- D. \( 1 + \frac{\pi}{4} \)
Solution
The correct option is **A**. (A. \( 1 + \frac{\pi}{2} \))
