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Jee Main 2025Medium JEE math MCQ

Let $f(x)$ be a real differentiable function such that $f(0) = 1$ and $f(x + y) = f(x)f(y) + f'(x)f(y)$ for all $x, y \in \mathbb{R}$. Then $\sum_{n=1}^{100} \log_2 f(n)$ is equal to
  1. A. 2525
  2. B. 5220
  3. C. 2384
  4. D. 2406

Solution

The correct option is **A**. (A. 2525)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
Let f(x)f(x) be a real differentiable function such that f(0)=1f(0) = 1 and f(x+y)=f(x)f(y)+f(x)f(y)f(x + y) = f(x)f(y) + f'(x)f(y) for all x,yRx, y \in \mathbb{R}. Then n=1100log2f(n)\sum_{n=1}^{100} \log_2 f(n) is equal to
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep