Thermodynamics — Medium JEE chemistry MCQ
One mole of an ideal gas at $300 \mathrm{~K}$ in thermal contact with surroundings expands isothermally from $1.0 \mathrm{~L}$ to $2.0 \mathrm{~L}$ against a constant pressure of $3.0 \mathrm{~atm}$. In this process, the change in entropy of surroundings $\left(\Delta S_{\text {surr }}\right)$ in $\mathrm{J} \mathrm{K}^{-1}$ is
(1 $\mathrm{L} \operatorname{atm}=101.3 \mathrm{~J})$
- A. 5.763
- B. 1.013
- C. -1.013
- D. -5.763
Solution
The correct option is **C**.
