Thermodynamics — Easy JEE chemistry MCQ
In an isothermal expansion of an ideal gas, 500 J of heat is absorbed by the system. The work done by the gas is:
- A. 500 J
- B. -500 J
- C. 0 J
- D. 250 J
Solution
From the first law of thermodynamics:
\[
\Delta U = Q - W
\]
For an isothermal process involving an ideal gas, \(\Delta U = 0\) (internal energy depends only on temperature).
Therefore:
\[
0 = Q - W \quad \Rightarrow \quad W = Q = 500\,\text{J}
\]
So the correct option is A.